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1.4x^2-2x-1=0
a = 1.4; b = -2; c = -1;
Δ = b2-4ac
Δ = -22-4·1.4·(-1)
Δ = 9.6
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-\sqrt{9.6}}{2*1.4}=\frac{2-\sqrt{9.6}}{2.8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+\sqrt{9.6}}{2*1.4}=\frac{2+\sqrt{9.6}}{2.8} $
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